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x^2-6x-391^2=0
We add all the numbers together, and all the variables
x^2-6x-152881=0
a = 1; b = -6; c = -152881;
Δ = b2-4ac
Δ = -62-4·1·(-152881)
Δ = 611560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{611560}=\sqrt{4*152890}=\sqrt{4}*\sqrt{152890}=2\sqrt{152890}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{152890}}{2*1}=\frac{6-2\sqrt{152890}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{152890}}{2*1}=\frac{6+2\sqrt{152890}}{2} $
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